Đồ án Lập trình thiết kế bộ nguồn cho động cơ một chiều bằng ngôn ngữ c++
Nội dung file nguồn *. Cpp
#include
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Ch¬ng tÝnh thiÕt kÕ bé nguån
cho ®éng c¬ ®iÖn mét chiÒu b»ng ng«n ng÷ C++
Néi dung file nguån *. Cpp
#include
#include
#include
main()
{
float D,Nmax,Mmax,ss ;//bien so cong nghe
float Uf1,Uf2,f,doondinh; // bien du lieu nguon
float Ud,Id,Ru,Ndm,Pd,p,cuonbu ; //bien du lieu dong co
float Ulv,Ilv,Ihd, Un,Unv,Idm,Ir,deltaUv; //bien thong so cua van
float If1,If2,S,n,l,deltaP,Ud0; // bien so cua bien ap
float Qfe,h,d,tiso,Bt,bfe,a,b,c,H,C,dfe; // bien trung gian mach tu MBA
float W1,W2,d1,d2,dn1,dn2,J1,J2,S1,S2,l1,l2;// bien trung gian day quan
float W11,h2,W12,n12,Dt2,Dn2,cd22,Bd2;//bien trung gian kat cau
float Dn1,Dtb1,cd01,h1,hg,Kc,n11,S01,Dt,Dt1,cd11,Bd1,a01,nl;
float a1,a2,b1,b2,dn11,dn22; //bien thong so day quan chu nhat
float Dtb2,D12,r12,a22; // cac thong so con lai cua MBA
float deltaUba,cdt,cdn,Bd;
float Mcu1,Mcu2,Mcu;
float R1,R2,Rba,Xba,Rbk,Lba,Zba,deltaPn;
float Unr,Unx,deltaUr,deltaUx;
float g,gmax,Udmin,Ukn,U1n,U1m;
float L,Lu,t,Lk;//bien tinh toan cuon khang
float Zk,deltaUk,Sk,Qk,ak,bk,ck,Wk,mk,adk,bdk;
float Jk,Ik,Qcsk,kld,hk,hgk,n1k,a01k,cd1k;
float Bdk,Bdtk,l1k,l2k,ltbk,Vfek,Mfek,Mcuk;
float Btk,Hk,Ck,W1k,Rk;
int sopha,k, chedo;
float pi=3.141592654;
textcolor(3);// thay doi mau cua chu
clrscr();
cout<<"\n CHUONG TRINH TINH BO NGUON CHO DC DIEN MOT CHIEU";
cout <<"\n BAN CO THE CHON CHE DO TINH TOAN ";
cout<<"\n co hai che do : ban tu dong va che do ban tu chon";
cout<<"\n NEU CHON BAN TU DONG THI AN (1) ";
cout <<"\n CHE DO TU BAN CHON KICH THUOC THI AN (2) ";
cin>>chedo;
cout<<"\n CAC THONG SO CONG NGHE";
cout<<"\n dai dieu chinh toc do D=";
cin>>D;
cout<<"\n toc do lon nhat(vong/phut) Nmax=";
cin>>Nmax;
cout<<"\n momem lon nhat Mmax=";
cin>>Mmax;
cout<<"\n sai so toc do cho phep ss=";
cin>>ss;
cout<<"\n THONG SO CUA NGUON";
cout<<"\n dien ap pha(V) Uf1 =";
cin>>Uf1;
cout<<"\n tan so cua nguon (Hz) f=";
cin>>f;
cout<<"\n do on dinh cua nguon ondinh=";
cin>>doondinh;
cout<<"\n so pha cua nguon sopha=";
cin>>sopha;
if ((sopha!=1)&(sopha!=3))
{
cout<<"\n ban vao sai so pha, hay vao lai so pha chi bang 1hoac 3";
cout<<"\n sopha=";
cin>>sopha;
}
cout<<"\n CAC THONG SO DONG CO";
cout<<"\n cong suat dong co(W) Pd=";
cin>>Pd;
cout<<"\n dien ap dong co(V) Ud=";
cin>>Ud;
cout<<"\n dong dien dong co (A)Id=";
cin>>Id;
cout<<"\n dien tro phan ung dong co(om) Ru=";
cin>>Ru;
cout<<"\n toc do dinh muc dong co(vong/phut) Ndm=";
cin>>Ndm;
cout<<"\n vao so doi cuc dong co p=";
cin>>p;
cout<<”\n DA NHAP DU CAC THONG SO CAN THIET, AN ENTER DE TIEP TUC”;
getch();
clrscr();
textcolor(12);
if (sopha==3)
{
cout<<"\n nguon dien xoay chieu ba pha";
cout<<"\n chon so do chinh luu la chinh luu cau 3 pha dieu khien doi xung";
cout<<"boi vi tai la dong co dien mot chieu co yeu cau tra nang luong ve luoi";
Ulv = ((pi/3)*Ud);
Unv=1.8*Ulv;
Ihd=0.71*Id;
}
else if (sopha==1)
{
cout<<"\n nguon dien xoay chieu mot pha";
cout<<"\n chon so do chinh luu la chinh luu cau 1 pha dieu khien doi xung";
cout<<"boi vi tai la dong co dien mot chieu co yeu cau tra nang luong ve luoi";
Ulv = 1.57135*Ud;
Unv=1.8*Ulv;
Ihd=0.7071*Id*2;
}
cout<<"\n dien ap nguoc toi thieu cua van la(V) Unv="<<Unv;
cout<<"\n dong dien lam viec toi thieu cua van la (A)Ilv="<<Ihd;
cout<<"\n voi cac gia tri tren ban chon van thich hop voi cac thong so cua van";
cout<<"\n dien ap nguoc cua van la(V) Unv=";
cin>> Unv;
cout<<"\n dong dien dinh muc cua van la(A) Idm=";
cin>>Idm;
cout<<"\n sut ap tren van la(V) dletaUv=";
cin>>deltaUv;
cout<<"\n dong dien ro qua van la(A) Ir=";
cin>>Ir;
cout<<”\n DA NHAP DU THONG SO VAN, AN ENTER DE TIEP TUC”;
getch();
deltaP= deltaUv*Idm;
if (deltaP<=20)
cout<<"\n chon dieu kien lam mat cua van la lam mat tu nhien";
else if ((deltaP>20)&(deltaP<=40))
{
cout<<"\n chon dieu kien lam mat cua van la";
cout<<" co canh toa nhiet voi day du dien tich lam mat khong co quat doi luu";
}
else if ((deltaP>40)&(deltaP<100))
{
cout<<"\n chon dieu kien lam mat cua van la";
cout<<" co canh toa nhiet va co quat doi luu";
}
else
{
cout<<"\n chon dieu kien lam mat cua van la ";
cout<<"co canh toa nhiet va lam mat cuong buc";
}
S=1.05*Pd;
deltaUba=0.07*Ud;
Ud0=(Ud+(2*deltaUv)+deltaUba)/cos(10*pi/180);
if (sopha==3)
{
Uf2=Ud0/2.34;
If2=sqrt(2.0/3.0)*Id;
If1=(Uf2*If2)/Uf1;
}
else if (sopha==1)
{
Uf2=Ud0/0.9;
If2= sqrt(2.000)*Id;
If1=(Uf2*If2)/Uf1;
}
cout<<"\n cong suat may bien ap la(VA) Sba="<<S;
cout<<"\n dien ap pha so cap may bien ap(V) Uf1="<<Uf1;
cout<<"\n dien ap pha thu cap may bien ap la(V) Uf2="<<Uf2;
cout<<"\n dong dien pha so cap may bien ap(A) If1="<<If1;
cout<<"\n dien ap pha thu cap may bien ap(A) If2 ="<<If2;
Qfe=6.0*sqrt(S/(sopha*f));
if (S>=10000)
{
cout<<"\n CHON TRU THEP CO TIET DIEN TRON ";
d=ceil(sqrt((4*Qfe/pi)));
cout<<"\n duong kinh tru la(cm) d="<<d;
if (chedo==2)
{
cout<<"\n chon ti so chieu cao va duong kinh tru h/d=";
cin >>tiso;
cout<<"\n trong do d: duong kich cua tru";
cout<<"\n h: chieu cua tru";
}
else if (chedo==1)
tiso=2.5;
h=ceil(d*tiso);
cout<<"\n chieu cao tru thep la(cm) h="<<h;
}
else
{
cout<<"\n CHON TRU THEP TIET DIEN HINH CHU NHAT ";
if (chedo==2)
{
cout<<"\n ta co cac ti so tuong ung la tiso=h/a, ";
cout<<"n=c/a,l=b/a,theo kinh nghiem ta co tiso=2.5,n=1.5,l=1den1.5";
cout<<"\n trong do a: la be rong cua tru";
cout<<"\n b: be day cua tru";
cout<<"\n c: be rong cua so mach tu";
cout<<"\n h: chieu cao cua so mach tu";
cout<<"\n ban chon cac ti so tuong ung";
cout<<"\n ti so giua chieu cao cua so va be rong tru h/a=";
cin>>tiso;
cout<<"\n ti so giua be rong cua cua so va be rong cua tru la c/a=";
cin>>n;
cout<<"\n ti so giua be day va be rong cua tru b/a=";
cin>>l;
}
else if (chedo==1)
{
tiso=2.5;
n=1.5;
l=1.5;
}
a=ceil(sqrt(Qfe/l));
b=ceil(l*a);
c=ceil(n*a);
h=ceil(tiso*a);
cout<<"\n be rong cua tru la(cm) a="<<a;
cout<<"\n be day cua tru la(cm) b="<<b;
cout<<"\n chieu rong cua so mach tu la(cm) c="<<c;
cout<<"\n chieu la cua so mach tu(cm) h="<<h;
H=a*2+h;
C=2*c+3*a;
cout<<"\n chieu cao mach tu la (cm) H="<<H;
cout<<"\n chieu dai mach tu la (cm) C="<<C;
}
if (chedo==2)
{
cout<<"\n chon loai thep co be day (mm) bfe=";
cin>>bfe;
cout<<"\n chon mat do tu cam cua thep la (T) Bt=";
cin>>Bt;
}
else if (chedo==1)
{
bfe=0.5;
Bt=1.0;
}
W1=ceil((Uf1*10000)/(4.44*f*Qfe*Bt));
W2=ceil(Uf2*W1/Uf1);
cout<<"\n so vong day so cap may bien ap la(vong) W1="<<W1;
cout<<"\n so vong day thu cap may bien ap la(vong) W2="<<W2;
cout<<"\n TINH TOAN THONG SO DAY SO CAP MAY BIEN AP";
{
if (chedo==2)
{
cout<<"\n chon mat do dong dien trong day quan so cap(A/mm) J1=";
cin>>J1;
cout<<"\n chon mat do dong dien trong day quan thu cap(A/mm) J2=";
cin>>J2;
}
else if (chedo==1)
{
J1=2.75;
J2=2.75;
}
S1=If1/J1;
cout<<"\n tiet dien day so cap theo tinh toan (mm2) S1="<<S1;
if (S1>4.0)
{
cout<<"\n CHON DAY DAN TIET DIEN HINH CHU NHAT";
cout<<"\n chuan hoa kich thuoc be day day dan(mm) a1=";
cin>>a1;
cout<<"\n chieu rong day dan(mm) b1=";
cin>>b1;
S1=a1*b1;
dn1=b1;
dn11=a1;
}
else
{
cout<<"\n CHON DAY DAN TIET DIEN TRON";
d1=sqrt(4.0*S1/pi);
cout<<"\n duong kinh day quan so cap(mm) d1="<<d1;
cout<<"\n duong kinh day quan so cap theo chuan hoa(mm) d1=";
cin>>d1;
cout<<"\n tiet dien day so cap theo chuan hoa(mm2) S1=";
cin>>S1;
cout<<"\n duong kinh ngoai day so cap ke ca cach dien (mm) dn1=";
cin>>dn1;
dn11=dn1;
}
J1=If1/S1;
cout<<"\n mat do dong dien day so cap theo tinh toan la(A/mm) J1="<<J1;
}
cout<<"\n TINH TOAN THONG SO DAY QUAN THU CAP";
{
S2=If2/J2;
cout<<"\n tiet dien day thu cap theo tinh toan la (mm2) S2="<<S2;
if (S2>4)
{
cout<<"\n CHON DAY DAN TIET DIEN HINH CHU NHAT";
cout<<"\n chuan hoa kich thuoc chieu day day (mm) a2=";
cin>>a2;
cout<<"\n chieu rong day(mm) b2=";
cin>>b2;
S2=a2*b2;
dn2=b2;
dn22=a2;
}
else
{
cout<<"\n CHON DAY DAN TIET DIEN TRON";
d2=sqrt(4.0*S2/pi);
cout<<"\n duong kinh day thu cap theo tinh toan la (mm) d2="<<d2;
cout<<"\n duong kinh day thu cap theo chuan hoa (mm) d2=";
cin>>d2;
cout<<"\n duong kinh ngoai day thu cap la (mm) dn2=";
cin>>dn2;
cout<<"\n tiet dien day theo chuan hoa(mm) S2=";
cin>>S2;
dn22=dn2;
}
J2=If2/S2;
cout<<"\n mat do dong dien day thu cap theo tinh toan la(mm) J2="<<J2;
}
cout<<"\n KET CAU DAY SO CAP";
cout<<"\n chon be day ong day bang vat lieu cach dien (mm) S01=";
cin>>S01;
if (chedo==2)
{
cout<<"\n chon he so ep chat Kc=";
cin>>Kc;
cout<<"\n chon cach dien giua cac lop day cuon so cap(mm) cd11=";
cin>>cd11;
cout<<"\n chon be day cach dien giua hai cuon day la(mm) cd01=";
cin>>cd01;
cout<<"\n chon cach dien giua cac lop day thu cap(mm) cd22=";
cin>>cd22;
cout<<"\n chon be day cach dien trong la(mm) cdt=";
cin>>cdt;
cout<<"\n chon be day cach dien ngoai(mm) cdn=";
cin>>cdn;
}
else if (chedo==1)
{
Kc=0.95;
cd11=0.1;
cd01=1;
cd22=0.1;
cdt=1;
cdn=1;
}
hg=S01;//khoang cach tu gong toi cuon so cap
W11=(h*10-2*hg)*Kc/dn1;
n11=ceil(W1/W11);
W11=floor(W1/n11);
cout<<"\n so lop day cuon so cap la(lop) n11="<<n11;
cout<<"\n so vong day so cap tren moi lop la(vong/lop) W11="<<W11;
h1=W11*dn1/Kc;//chieu cao thuc te cuon day so cap
a01=10;//khoang cach tu tru toi cuon day so cap
cdt=S01;
if (S>10000)
Dt1=d*10+2*a01;
else
{
Dt1=10*sqrt(a*a+b*b)+2*cdt;
}
Bd1=(dn11+cd11)*n11;
Dn1=Dt1+2*Bd1;
Dtb1=(Dt1+Dn1)/2;
l1=(W1*pi*Dtb1)/1000;
cout<<"\n chieu dai day quan so cap la(m) l1="<<l1;
cout<<"\n KET CAU DAY THU CAP";
h2=h1;
W12=h2*Kc/dn2;
n12=ceil(W2/W12);
W12=floor(W2/n12);
h2=W12*dn2/Kc;
Dt2=Dn1+2*cd01;
Bd2=(dn22+cd22)*n12;
Bd=Bd1+Bd2+cdt+cdn;
Dn2=Dt2+2*Bd2;
Dtb2=(Dt2+Dn2)/2.0;
l2=W2*pi*Dtb2/1000.0;
cout<<"\n so lop day cua cuon day thu cap (lop) n12="<<n12;
cout<<"\n so vong tren moi lop (vong/lop) W12="<<W12;
cout<<"\n chieu dai day quan thu cap (m) l2="<<l2;
cout<<"\n tinh khoi luong dong";
if (sopha==3)
{
Mcu1=S1*l1*8.9*3*0.001;
Mcu2=S2*l2*8.9*3*0.001;
}
else if (sopha==1)
{
Mcu1=S1*l1*8.9*0.001;
Mcu2=S2*l2*8.9*0.001;
}
Mcu=Mcu1+Mcu2;
cout<<"\n KHOI LUONG DONG 1 CUON SO CAP(kg) Mcu1="<<Mcu1;
cout<<"\n KHOI LUONG DONG 1 CUONG THU CAP (kg) Mcu2="<<Mcu2;
cout<<"\n TONG KHOI LUONG DONG (kg) Mcu="<<Mcu;
float r75=0.02133;
R1=r75*l1/S1;
R2=r75*l2/S2;
Rba=R2+R1*(W2/W1)*(W2/W1);
deltaUr=Rba*Id;
Rbk=Dt2/2; //ban kinh trong cuon day thu capmay bien ap
Xba=16*pi*pi*W2*W2*(Rbk/h)*(cd01+(Bd1+Bd2)/3)*0.001*pi*f*0.0000001;
Lba=Xba/(2*pi*f);
if (sopha==3)
{
deltaUx=3*Xba*Id/pi;
deltaPn=3*Rba*Id*Id;
Unr=3*Rba*If2*100/Uf2 ;
}
else if (sopha==1)
{
deltaUx=Xba*Id/pi;
deltaPn=Rba*Id*Id;
Unr=Rba*If2*100/Uf2 ;
}
deltaUba=sqrt(deltaUr*deltaUr+deltaUx*deltaUx);
Zba=sqrt(Rba*Rba+Xba*Xba);
deltaP=deltaPn*100/S;
Unx=Xba*If2*100/Uf2;
Un=sqrt(Unr*Unr+Unx*Unx);
cout<<"\n dien tro cuon so cap(om) R1="<<R1;
cout<<"\n dientro cuong thu cap(om) R2="<<R2;
cout<<"\n dien tro may bien ap(om) Rba="<<Rba;
cout<<"\n dien cam may bien ap(om) Xba="<<Xba;
cout<<"\n tong sut ap(V) deltaUba="<<deltaUba;
cout<<"\n cong suat ton hao ngan mach(%) deltaP="<<deltaP;
cout<<"\n dien ap ngan mach(%) Un="<<Un;
cout<<"\n XAC DINH THANH PHAN SONG HAI ";
Udmin=(2.34*Uf2*cos(10*pi/180)+(D-1)*Id*(Ru+Rba+3*Xba/pi))/D;
t=Udmin/Ud0;
cout<< "\n goc mo lon nhat la goc co arcos(goc)= "<<t;
cout<<"\n vao bac song hai can tinh k=";
cin>>k;
cout<<"\n vao gia tri goc cua song hai can tinh(do) g=";
cin>>g;
Ukn=3*sqrt(6)*Ud0*sqrt(1+36*k*k*tan(g*pi/180)*tan(g*pi/180))/(pi*(36*k*k-1));
cout<<"\n tri so cua song hai voi bac va";
cout<<"goc tuong ung la(V) Ukn="<<Ukn;
U1m=2*Ud0*t*sqrt(1+36.0*(1/(t*t)-1))/35.0;
L=U1m/(1.2*pi*f*Id);
Lba=Xba/(2*pi*f);
cout<<"\n dong co co cuon bu khong ? neu co thi an 1, khong thi an 2 ";
cin>>cuonbu;
if (cuonbu==1)
{
Lu=0.25*Ud*30.0/(pi*Ndm*Id*p);
}
else if (cuonbu==2)
{
Lu=0.55*Ud*30/(pi*Ndm*Id*p);
}
Lk=L-(Lu+2.00*Lba);
if (Lk<0)
{Lk=-Lk;}
else if (Lk>0)
Lk=Lk;
cout<<"\n dien cam cuon khang loc la (H) Lk="<<Lk;
Zk=2*pi*f*Lk;
deltaUk=Zk*Id/sqrt(2);
Sk=deltaUk*Id*0.1/sqrt(2);
Qk=5*100*sqrt(Sk/(6*f));
cout<<"\n tiet dien cuon khang theo tinh toan la(mm2) Qk="<<Qk;
cout<<"\n chon tiet dien cuon khang theo chuan hoa (mm2) Qk=";
cin>>Qk;
cout<<"\n tuong ung co be rong tru cuon khang (mm) ak=";
cin>>ak;
cout<<"\n va be day tru cuon khang (mm) bk=";
cin>>bk;
if (chedo==2)
{
cout<<"\n ty so hinh dang mk=hk/ak=";
cin>>mk;
cout<<"\n chon mat do tu cam trong tru(T) Btk=";
cin>>Btk;
cout<<"\n chon mat do dong dien qua cuon khang Jk=";
cin>>Jk;
cout<<"\n chon ty so lap day cuon khang la Kld=";
cin>>kld;
}
else if (chedo==1)
{
mk=2.5;
Btk=0.85;
Jk=2.5;
kld=0.75;
}
Wk=ceil(1000000*deltaUk/(4.44*f*Btk*Qk));
Ik=sqrt(Id*Id+(0.01*Id*Id/sqrt(2)));
Sk=Ik/Jk;
cout<<"\n tiet dien day quan cuon khang theo tinh toan la Sk="<<Sk;
cout<<"\n chuan hoa kich thuoc day";
cout<<"\n chieu day day quan la (mm) adk=";
cin>>adk;
cout<<"\n chieu rong day quan la(mm) bdk=";
cin>>bdk;
Sk=adk*bdk;
Jk=Ik/Sk;
Qcsk=Wk*Sk/kld;
hk=mk*ak;
ck=ceil(Qcsk/hk);
Hk=hk+ak;
Lk=2*ck+2*ak;
hgk=2;
W1k=floor((hk-2*hgk)/bk);
n1k=ceil(Wk/W1k);
a01k=3;
cd1k=0.1;
Bdk=(adk+cd1k)*n1k;
Bdtk=Bdk+a01k;
l1k=2*(ak+bk)+2*pi*a01k;
l2k=2*(ak+bk)+2*pi*(a01k+Bdk);
ltbk=(l1k+l2k)/2;
Rk=r75*ltbk*Wk*0.001/Sk;
Vfek=ak*bk*(2*hk+1);
Mfek=Vfek*7.85*0.001;
Mcuk=Sk*ltbk*Wk*0.001*8.9;
cout<<"\n CAC THONG SO CUON KHANG";
cout<<"\n tri so dien cam(H) Lk="<<Lk;
cout<<"\n so vong day cuon khang(vong) Wk="<<Wk;
cout<<"\n tiet dien day cuon khang(mm2) Sk="<<Sk;
cout<<"\n tiet dien tru cuon khang(mm2) Qk="<<Qk;
cout<<"\n dien tich cua so cuon khang(mm2) Qcsk="<<Qcsk;
cout<<"\n BAN ENTER DE XEM THONG SO DAU RA THEO YEU CAU";
getch() ;
{
clrscr();
textcolor(12);
cout<<"\n\n CAC THONG SO CUA MAY BIEN AP DONG LUC ";
cout<<"\n cong suat bien ap (VA) Sba="<<S;
cout<<"\n dien ap so cap may bien ap (V) Uf1="<<Uf1;
cout<<"\n dien ap thu cap may bien ap (V) Uf2="<<Uf2;
cout<<"\n dong dien so cap may bien ap (A) If1="<<If1;
cout<<"\n dong dien thu cap may bien ap (A) If2="<<If2;
cout<<"\n tiet dien day so cap may bien ap (mm2) S1="<<S1;
cout<<"\n tiet dien day thu cap may bien ap (mm2) S2="<<S2;
cout<<"\n tiet dien tru (mm2) Qfe="<<Qfe;
cout<<"\n dien cam may bien ap (H) Lba="<<Lba;
cout<<"\n dien tro may bien ap (om) Rba="<<Rba;
cout<<"\n tong sut ap may bien ap (V) deltaUba="<<deltaUba;
cout<<"\n ton hao cong suat ngan mach (W) deltaPn="<<deltaPn;
cout<<"\n dien ap ngan mach la (V) Un="<<Un;
cout<<"\n\n CAC DU LIEU CUON KHANG LOC";
cout<<"\n tri so dien cam (H) Lk="<<Lk;
cout<<"\n so vong day (vong) Wk="<<Wk;
cout<<"\n tiet dien day (mm2) Sk="<<Sk;
cout<<"\n tiet dien tru (mm2) Qk="<<Qk;
cout<<"\n dien tich cua so (mm2) Qcsk="<<Qcsk;
cout<<"\n\n DU LIEU CHAT LUONG NGUON";
cout<<"\n tri so song hai bac"<<k<<" goc"<<g<<"la(V) Ukn="<<Ukn;
cout<<"\n\n GHI SO LIEU VA THOAT CT BANG LENH ENTER";
}
getch( );
}
KÕt qu¶ ch¹y thö file *.exe
§Ò bµi víi c¸c th«ng sè cho nh sau:
C¸c d÷ liÖu c«ng nghÖ: D¶i ®iÒu chØnh D =100, tèc ®é lín nhÊt Nmax =1000 (vßng/phót), m«mmen lín nhÊt Mmax =200 (N.m ), sai sè tèc ®é cho phÐp lµ 5%.
C¸c d÷ liÖu nguån: ®iÖn ¸p 220/380 (V), tÇn sè f=50 (Hz), 3 pha , ®é æn ®Þnh nguån lµ 0,95.
C¸c d÷ liÖu ®éng c¬ : c«ng suÊt Pd = 27(Kw), ®iÖn ¸p Ud = 400(V), dßng ®iÖn Id =80(A), ®iÖn trë phÇn øng R = 0.38(W), tèc ®é ®Þnh møc n®m 980(vßng /phót).
®éng c¬ kh«ng cã cuén bï.
Qu¸ tr×nh nhËp vµ ch¹y kÕt qu¶. Ta tÝnh ë chÕ ®é b¸n tù ®éng :
KÕt qu¶ theo th«ng sè yªu cÇu cña ®Ò ra khi ch¹y file *.exe
§Ò bµi víi c¸c th«ng sè cho nh sau:
C¸c d÷ liÖu c«ng nghÖ: D¶i ®iÒu chØnh D =100, tèc ®é lín nhÊt Nmax =1000 (vßng/phót), m«mmen lín nhÊt Mmax =120 (N.m ), sai sè tèc ®é cho phÐp lµ 5%.
C¸c d÷ liÖu nguån: ®iÖn ¸p 220/380 (V), tÇn sè f=50 (Hz), 3 pha , ®é æn ®Þnh nguån lµ 0,95.
C¸c d÷ liÖu ®éng c¬ : c«ng suÊt Pd = 10(Kw), ®iÖn ¸p Ud = 220(V), dßng ®iÖn Id =50(A), ®iÖn trë phÇn øng R = 0.2(W), tèc ®é ®Þnh møc n®m= 970(vßng /phót).
®éng c¬ cã cuén bï.
Ta ch¹y ch¬ng tr×nh víi trêng hîp lµ tù chän c¸c th«ng sè
Qu¸ tr×nh tÝnh to¸n:
KÕt qu¶ cuèi cïng cña bµi to¸n lµ:
ThuyÕt minh ho¹t ®éng cña ch¬ng tr×nh
tÝnh bé nguån cho ®«ng c¬ ®iÖn mét chiÒu
I.TÝnh chän Thyristor:
TÝnh chän dùa vµo c¸c yÕu tè c¬ b¶n dßng t¶i, ®iÒu kiÖn to¶ nhiÖt, ®iÖn ¸p lµm viÖc, c¸c th«ng sè c¬ b¶n cña van ®îc tÝnh nh sau:
+ §iÖn ¸p ngîc lín nhÊt mµ Thyristor ph¶i chÞu:
Unmax=Knv.U2 =Knv .
Trong ®ã: Knv , Ku : tra trong tµi liÖu
§iÖn ¸p ngîc cña tiristor cÇn chän:
Unv = KdtU . Un max
Trong ®ã:
KdtU - hÖ sè dù tr÷ ®iÖn ¸p, chän KdtU =1,8 .
+ Dßng lµm viÖc cña van ®îc tÝnh theo dßng hiÖu dông:
Ilv = Ihd = Khd .Id
Tõ c¸c th«ng sè vÒ dßng ®iÖn lµm viÖc vµ ®iÖn ¸p ngîc th× ta chän van vµ nhËp c¸c th«ng sè theo yªu cÇu ®Ó ch¬ng tr×nh tiÕp tôc ch¹y
II.TÝnh to¸n m¸y biÕn ¸p chØnh lu.
NÕu nguån bµ pha th× ta chän m¸y biÕn ¸p 3 pha 3 trô s¬ ®å ®Êu d©y D/Y lµm m¸t b»ng kh«ng khÝ tù nhiªn .
NÕu lµ nguån mét pha th× ta chon m¸y biÕn ¸p 1 pha
TÝnh c¸c th«ng sè c¬ b¶n:
1. TÝnh c«ng suÊt biÓu kiÕn cña M¸y biÕn ¸p:
S = Ks . Pd
2. §iÖn ¸p s¬ cÊp m¸y biÕn ¸p:
U1 ®· cho.
3. §iÖn ¸p pha thø cÊp cña m¸y biÕn ¸p
Ph¬ng tr×nh c©n b»ng ®iÖn ¸p khi cã t¶i:
Udo .cos amin =Ud +2. DUv +DUdn + DUba (1.80)
Trong ®ã:
amin =100 lµ gãc dù tr÷ khi cã sù suy gi¶m ®iÖn líi
DUv lµ sôt ¸p trªn Thyristor
DUdn 0 lµ sôt ¸p trªn d©y nèi
DUba = DUr + DUx lµ sôt ¸p trªn ®iÖn trë vµ ®iÖn kh¸ng m¸y biÕn ¸p .
Tõ ph¬ng tr×nh c©n b»ng ®iÖn ¸p khi cã t¶i ta cã:
Ud0 =
§iÖ
Các file đính kèm theo tài liệu này:
hoan thanh(0905).doc- debai.doc
kien1105.rar
